-9=-10x-4.9x^2

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Solution for -9=-10x-4.9x^2 equation:



-9=-10x-4.9x^2
We move all terms to the left:
-9-(-10x-4.9x^2)=0
We get rid of parentheses
4.9x^2+10x-9=0
a = 4.9; b = 10; c = -9;
Δ = b2-4ac
Δ = 102-4·4.9·(-9)
Δ = 276.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{276.4}}{2*4.9}=\frac{-10-\sqrt{276.4}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{276.4}}{2*4.9}=\frac{-10+\sqrt{276.4}}{9.8} $

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